Craps Make Em All Bet
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Here to ask advice about the maths behind the make 'em all craps side bet.
For those who don't know, the bet is a wager that a shooter will roll every number 2-6 and 8-12 before rolling a 7.
I have seen the wizard's answers to the house edge on his site and it lines up with the brute force calculations I have seen simulated previously. However I was wondering if there was another way to do it? If anyone could point me in the right direction of where to look to start finding answers I would really appreciate it.
Similarly, if this has already been brought up somewhere else please point me towards it and I will be happy to read that!
Thanks in advance for any hints or pointers anyone can offer!
Here to ask advice about the maths behind the make 'em all craps side bet. For those who don't know, the bet is a wager that a shooter will roll every number 2-6 and 8-12 before rolling a 7. I have seen the wizard's answers to the house edge on his site and it lines up with the brute force calculations I have seen simulated previously. Betting in craps comes in different forms and there are different types of wagers you can make. When it’s your turn, you become the shooter. This means you’re the one rolling the dice and you are required to make a Pass Line bet or a Don’t Pass Line bet. This is a fundamental craps bet because it signifies a wager for the shooter to win. All “Make’em All” pays 175 - 1 The house edge is 7.76% for Small and Tall bets and 7.47% for the Make ‘em All bet with the paytable above. Some casinos offer lower payouts and with that have a.
Up to 21% edge these lower payout days, correct?But to clarify, you have 2^10 states as a result of having either made or not made each number correct? I'm not enough of an excel wiz to understand everything that's going on but most of it makes intuitive sense. I am curious as to how using the mod(floor ... gives you the 1024 different possible orders like it does? Is there any chance you could dumb that down for me a tiny bit? haha
Also, the reason I stopped trying to make a sheet like that, is I thought maybe I could find a formula to solve the whole thing?
For example, P(9)= 4/36 P(7or9)1=10/36 -> P(7 7or9) = 1/9 / 5/18 = 1/9 * 18/5 = 2/5 which is obv why the odds bet pays 3/2.
Anyway, if i can do that, can I not do a formula for odds of a 5 and a 9 before a seven? I don't honestly even know if its possible just seems like to me that it should be! If you can give me any advice as well regarding that I would be very grateful!
Cheers for your time, man.
Up to 21% edge these lower payout days, correct?
That's easy peasy for you DI people to beat, right??
How about the new payouts, 30-1 and 150-1? Reply to Miplet
Yes the new payouts suck. 18.3% and 20.6% if those are 'to 1' pays.Thanks Miplet! That really helpful! I started doing something similar and then thought I might be trying too hard so stopped haha.
But to clarify, you have 2^10 states as a result of having either made or not made each number correct? I'm not enough of an excel wiz to understand everything that's going on but most of it makes intuitive sense. I am curious as to how using the mod(floor ... gives you the 1024 different possible orders like it does? Is there any chance you could dumb that down for me a tiny bit? haha
Also, the reason I stopped trying to make a sheet like that, is I thought maybe I could find a formula to solve the whole thing?
For example, P(9)= 4/36 P(7or9)1=10/36 -> P(7 7or9) = 1/9 / 5/18 = 1/9 * 18/5 = 2/5 which is obv why the odds bet pays 3/2.
Anyway, if i can do that, can I not do a formula for odds of a 5 and a 9 before a seven? I don't honestly even know if its possible just seems like to me that it should be! If you can give me any advice as well regarding that I would be very grateful!
Cheers for your time, man.
The =mod(floor(X,Y,1),2) formula was what I came up with to get the individual bits from a number. X is the number and Y is the bit (always a power of 2). Let's do 5 for example
1s bit. mod(floor(5,1,1),2) 5/1=5 and the remainder of 5/2 is 1
2s bit. mod(floor(5,2,1),2) 5/2=2 when rounded down and the remainder of 2/2 is 0
4s bit. mod(floor(5,4,1),2) 5/4=1 when rounded down and the remainder of 1/2 is 1
8s bit. mod(floor(5,8,1),2) 5/8=0 when rounded down and the remainder of 0/2 is 0
16s bit and higher are all like 8s bit and end up as 0
The All, Small, or Tall bets are made at the beginning of the shooter's hand - when he first gets the dice. You can bet any or all three of the bets. There are a lot of ways to play it. I've see guys toss out $5 and get $2 each on the Small and Tall and $1 on the All. I've also seen it go the other way, a buck each on the Small and Tall and $3 on the All. Or you could just toss out $3 and bet all three for a buck each. You can put me in that category. I consider it a 'recreational' bet - in the same category as Fire Bets, Harways, Horns and Hop Bets. I also like to use the All, Tall, and Small as dealer toke bets. Yeah, dealers would rather have a hand-in. But I'd rather have them in the game.
The Small and Tall bets pay $35 to 1 on the layouts I've seen.
The ALL pays $175 to 1.
WOW
If you want to get into the odds of scoring on any of these bets I'll simply refer you to the wizard of odds website. http://wizardofodds.com/craps/appendix4.html#smalltall
I will tell you that I've hit the ALL bet twice. On a long hand it can happen. The last time I hit it I tossed FOREVER trying to throw aces. Finally hit it on a Come Out roll, winning both the ALL and the World High-Low combo I often play on the come out. Yeah, that was $230 minus my $10 Pass Line bet.
The idea I've seen bandied about on other websites revolves around a strategy we often use when going for the sixth number in the Fire Bet - laying against the point to guarantee a win. Can this idea be profitably applied to the All, Small or Tall as well? The answer is - maybe.
Craps Make Em All Bet Odds
Let's say you're shooting for the ten to complete the bet. If you make the ten you'll win $175 plus your pass line bet and odds. But who's to say you have to shoot from the right side? Why not play $25 on the DP and lay $50 to guarantee yourself $50 if you seven out or net $100 if you make the point? Seems like a logical approach to me.Craps Make Em All Bet Poker
On another tack - if your remaining point is the two three, eleven, or twelve - will the casino book a 'No Twelve' bet? I don't think so. But even if they did you'd bet betting something like $39 to win $1 (or whever they put the breakage). Not a logical play in my book.
Sooooo, that gets us down to the point where I'd like some participation from you guys. How many of you have played the All, Small or Tall bet? Where did you play it? What was your approach to the bet. Did you have any success at it?
I know Irish has hit it because he and about have of the class showed up at the dealer school in Vegas something like an hour and a half late because he had the dice and was not giving them back.
Craps Make Em All Betting
Stories?Let's hear 'em.
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